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Simpleton

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Since: Nov 09, 2005
Posts: 158

(Msg. 1) Posted: Sun Feb 12, 2006 9:31 am
Post subject: question for Ricky
Archived from groups: rec>sport>jetski (more info?)

Since you claim to have a handle on this answer me this:
1) what is the tuning frequency of the balance shaft in your Sea Doo?
2) what is the natural frequency of your hull?
3) what is the relationship between the two?

>> Stay informed about: question for Ricky

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Since: Nov 09, 2005
Posts: 839

(Msg. 2) Posted: Sun Feb 12, 2006 2:57 pm
Post subject: Re: question for Ricky [Login to view extended thread Info.]
Archived from groups: per prev. post (more info?)

1) what is the tuning frequency of the balance shaft in your Sea Doo?

Which frequency, FID, FIC, FIIC or FIID

R

>> Stay informed about: question for Ricky

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Since: Nov 09, 2005
Posts: 839

(Msg. 3) Posted: Sun Feb 12, 2006 4:33 pm Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

In SI units, angular frequency is measured in radians per second, or RPM Angular frequency is not measure in hertz, it's either mesured as RPM or rad/sec, anymore stupid questions you need answered. R >> Stay informed about: question for Ricky

Simpleton

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Since: Nov 09, 2005
Posts: 158

(Msg. 4) Posted: Sun Feb 12, 2006 4:53 pm Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

While we wait on Ricky's reply, please enjoy another offering from the "No Balance Shafts" video library..... Jake does 10.66@139mph http://www.llarian.net/~gomer/evil_eaglecompilation%20video.wmv "Simpleton" <simpleton RemoveThis @yahoo.com> wrote in message news:JOadnWVht-1N23LenZ2dnUVZ_sadnZ2d@comcast.com... > Since you claim to have a handle on this answer me this: > 1) what is the tuning frequency of the balance shaft in your Sea Doo? > 2) what is the natural frequency of your hull? > 3) what is the relationship between the two? > >> Stay informed about: question for Ricky

Simpleton

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Since: Nov 09, 2005
Posts: 158

(Msg. 5) Posted: Sun Feb 12, 2006 6:39 pm Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

Allow me to rephrase the question for you. What is the frequency in Hz. that the ballance shaft attempts to null? "R" <rgere70_4.TakeThisOut@msn.com> wrote in message news:1139785023.813699.55620@g14g2000cwa.googlegroups.com... > 1) what is the tuning frequency of the balance shaft in your Sea Doo? > > Which frequency, FID, FIC, FIIC or FIID > > R > >> Stay informed about: question for Ricky

The_Giz

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Since: Feb 24, 2005
Posts: 115

(Msg. 6) Posted: Mon Feb 13, 2006 1:03 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

What's the matter Prichard? Unable to answer this relatively simple question? Couldn't find it in the softback edition of "Doos for Dummies"? He never said a thing about angular frequency. Giz >> Stay informed about: question for Ricky

Simpleton

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Since: Nov 09, 2005
Posts: 158

(Msg. 7) Posted: Mon Feb 13, 2006 1:03 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

Nope, never asked a thing about angular freq. What is the frequncy that the shaft attemps to null in Hz? What is the natural frequency of the craft? What is the relationship between the two? I'm starting to sound like Dan Rather's mugger.... http://www.ratherbiased.com/audio/frequency.mp3 "The_Giz" <The_Giz.TakeThisOut@Hotmail.com> wrote in message news:nVQHf.4286$iD.2482@tornado.rdc-kc.rr.com... > What's the matter Prichard? Unable to answer this relatively simple > question? Couldn't find it in the softback edition of "Doos for Dummies"? > > He never said a thing about angular frequency. > > Giz > >> Stay informed about: question for Ricky

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Since: Nov 09, 2005
Posts: 839

(Msg. 8) Posted: Mon Feb 13, 2006 1:20 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

Well I got nuthin to do again, since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius l = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin angle(theta + alpha)refer to url magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/l, derived from the agnle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/l[sin(theta + alpha)] or mw^2r^2/l[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

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Since: Nov 09, 2005
Posts: 839

(Msg. 9) Posted: Mon Feb 13, 2006 2:37 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

Why should I answer your questions, your both posers. R >> Stay informed about: question for Ricky

External

Since: Nov 09, 2005
Posts: 839

(Msg. 10) Posted: Mon Feb 13, 2006 2:43 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

Well I got nuthin to do again, since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius l = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin angle(theta + alpha)refer to url magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/l, derived from the angle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/l[sin(theta + alpha)] or mw^2r^2/l[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

External

Since: Nov 09, 2005
Posts: 839

(Msg. 11) Posted: Mon Feb 13, 2006 3:27 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

Since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius b = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin angle(theta + alpha)refer to url theta = wt magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/b, derived from the angle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/b[sin(theta + alpha)] or mw^2r^2/b[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

External

Since: Nov 09, 2005
Posts: 839

(Msg. 12) Posted: Mon Feb 13, 2006 3:38 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

url http://pdmec4.mecc.unipd.it/ Since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius b = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin angle(theta + alpha)refer to url theta = wt magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/b, derived from the angle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/b[sin(theta + alpha)] or mw^2r^2/b[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

External

Since: Nov 09, 2005
Posts: 839

(Msg. 13) Posted: Mon Feb 13, 2006 3:41 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

url http://pdmec4.mecc.unipd.it/DINAMOTO/on-line%20papers/twin%20motors/twin.html Since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius b = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin angle(theta + alpha)refer to url theta = wt magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/b, derived from the angle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/b[sin(theta + alpha)] or mw^2r^2/b[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

External

Since: Nov 09, 2005
Posts: 839

(Msg. 14) Posted: Mon Feb 13, 2006 4:27 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

url http://pdmec4.mecc.unipd.it/DINAMOTO/on-line%20papers/twin%20motors/t... Since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius b = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin w = angular velocity angle(theta + alpha)refer to url theta = wt alpha = cylinder phase magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/b, derived from the angle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/b[sin(theta + alpha)] or mw^2r^2/b[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

External

Since: Nov 09, 2005
Posts: 839

(Msg. 15) Posted: Mon Feb 13, 2006 4:32 am Post subject: Re: question for Ricky [Login to view extended thread Info.] Archived from groups: per prev. post (more info?)

url http://pdmec4.mecc.unipd.it/DINAMOTO/on-line%20papers/twin%20motors/twin.html Since fiz is a poser, I derived both inertia force equations. F = ma r = crank radius b = conrod length m = mass(look at url) a = centrifigal acceleration at crank pin w = angular velocity angle(theta + alpha)refer to url theta = wt alpha = cylinder phase magnitude of a parallel to crank raduis = w^2r magnitude of a parallel to conrod axis = w^2r^2/b, derived from the angle cot(theta + alpha) First order force parallel to piston axis = mw^2r[cos(theta + alpha)] Second order force parallel to piston axis = mw^2r^2/b[sin(theta + alpha)] or mw^2r^2/b[cos2(theta + alpha)] fiz your a poser, fake ME R >> Stay informed about: question for Ricky

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